Chemistry, asked by bigshow123, 1 year ago

for the reaction CO2(g) + C(s) <<>>2CO(g),the partial pressure of co2 and co are 2 and 4atm at equilibrium .the kp of the reaction

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Answered by aqibkincsem
35

CO₂ (g) + C (s) <==> 2CO (g) Kp articulation for given response is Kp = (Partial weight of CO)²/(Partial weight of CO₂) = (4²/2) atm = 8 atm Kp of response is 8 atm.

CO2 weight diminishes let it be `x`then increment in weight because of CO after response is 2xtotal weight = (0.5-x) + 2x = 0.8 ATMX=0.3 ATMthus weight of CO2 = 0.2and CO= 0.6K = P^2 CO ÷ P CO2 = 1.8.

Answered by QHM
56
Kp for the reaction is 8 atm.
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