The diameter of a flywheel is 1m. It has a mass of 20 kg. It is rotating about its axis with a speed of 120 rotations in one minute. Its angular momentum in kg.m2/s is
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L=Iw(Omega).
n=no.of rotations/1min=120/60=2
n=2
w=2πn=2×π×2=4π
I=mr×r/2=20×1/2×1/2/2=5/2
L=5/2×4π=5/2×4×22/7=220/7=31.4
n=no.of rotations/1min=120/60=2
n=2
w=2πn=2×π×2=4π
I=mr×r/2=20×1/2×1/2/2=5/2
L=5/2×4π=5/2×4×22/7=220/7=31.4
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angular momentum is 31.4 kgm²/s
moment of inertia of flywheel about its axis, I = 1/2 mr² , where r is radius of the flywheel.
= 1/2 × 20kg × (1/2 m)²
= 10kg × 1/4 m²
= 2.5 kgm²
angular speed, ω = 2πN/60 rad/s , where N is number of revolution per minute.
ω = 2π × 120/60 = 4π rad/s
now angular momentum, L = Iω
= 2.5 kgm² × 4π rad/s
= 10π kgm²/s
= 10 × 3.14 kgm²/s
= 31.4 kgm²/s
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