~For the reaction equilibrium,2NOBr (g) 2NO (g) + Br2(g), If P= P/9 at equilibrium and P is total pressure. The
ratio K/P is equal to
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2NOBr⇌2NO + Br2KP=(PNO)2(PBr2)(NOBr)2PBr2=P9 , P=total pressure at equilibriumLet the initial pressure be Pinitial, α be the degree of dissociationSo, at equilibrium, pressure of NO = 2PinitialαPressure of Br2 = PinitialαPressure of NOBr =Pinitial−2PinitialαTotal pressure at equilibrium = P = Pinitial−2Pinitialα +Pinitialα+2Pinitialα =Pinitial(1+α)
P=Pinitial(1+α) P = Pinitial +PinitialαPBr2=Pinitialα = P9So, P = Pinitial+P9Pinitial= P−P9 =8/9p
So, equilibrium pressure of NOBr = 89P−2×P9=69P Equilibrium pressure of NO =29PS
Kp ,= p/81
Kp/p = 1/81
P=Pinitial(1+α) P = Pinitial +PinitialαPBr2=Pinitialα = P9So, P = Pinitial+P9Pinitial= P−P9 =8/9p
So, equilibrium pressure of NOBr = 89P−2×P9=69P Equilibrium pressure of NO =29PS
Kp ,= p/81
Kp/p = 1/81
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