Question

factorize (2a-3y) 3+(3y-4z) 3+(4z-2x) 3 by identities

Answer 1

HELLO......FRIEND!!

THE ANSWER IS HERE,

(2a-3y)3+(3y-4z)3+(4z-2x)3.

Taking 3 as common.

=> (3)(2a-3y+3y-4z+4z-2x)

=> (3)(2a-2z)

=> (6)(a-z)


:-)Hope it helps u.

Answer 2

Hi Friend !!


Here is ur answer....,,,

(2a-3y) 3+(3y-4z) 3+(4z-2x) 3

Taking 3 as common.

= 3(2a-3y+3y-4z+4z-2x)

= 3(2a -2x)

= 6(a-x)


Hope it helps u : )