Question

For the reaction m n o 4 - + c2 o4 - 2 + h + gives mn + 202 + h2o the correct coefficients of reactants for the balanced equation

Answer 1

Balanced equation:

$2MnO_4^- + 5C_2O_4^{4-}+16H^+$→$2Mn^{2+}+10CO_2+8H_2O$

This reaction can be used for titration of oxalic acid using KMnO4 as self indicator

Answer 2

Answer:

The coefficient of the reactants are : 2, 5, 16

Explanation:

To answer this question we need to balance the equation.

First we rewrite the equation as below :

MnO4(-) + C2O4(2-) + H(+) —> Mn(2+) + CO2 + H2O

For the equation to balance we should have equal number of moles of each element on either sides.

Balancing the equation we have :

2MnO4(-) + 5C2O4(2-) + 16H(+) —> 2Mn(2+) + 10CO2 + 8H2O

From this we can get the coefficient of the reactants and the products.

The coefficients of the reactants : 2,5,16

The coefficient of products : 2, 10, 8