Question

For the reaction : N2O3(g)⇌NO(g) + NO2(g);
total pressure = P, degree of dissociation = 50%.
Then Kp would be​

Answer 1

Answer:

Explanation:

For the reaction given the total pressure is P atm and the amount of dissociation is 50%                 N2O3↔NO + NO2initial         1              0                0At time t     1−x       x                 xx=50% at pressure PKp=nNO.nNO2n N2O3.P=x.x1−x.P=(0.50)21−0.50.P=0.5P=P/2

Answer 2

Ur answer is :-

N₂O₃ ⇄ NO + NO₂

Consider the pressure of N₂O₃  as P

P             0           0

P - Pα     Pα         Pα

Keq = (Pα)²/P(1-α)

      = Pα²/(1-α)

      = P/4(1/2)

       =P/2

:) Hope this helps !!!

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