for the reaction N2O5(g)gives 2NO2(g)+1/2O2(g), thevalue of rate of disappearance of N2O5 is given as 6.25 * 10 ^-3 mol /litre /sec the rate of formation of NO2 and O2 is given respectively as
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18
Explanation:
-d[N2O5]/dt = +2d[NO2]/dt = 1/2d[O2]/dt
rate of formation of NO2 = (rate of disappearence of N2O5)/2
rate of formation of NO2 = 6.25*10^-3/2 = 3.125*10^-3
rate of formation of O2=rate of disappearence of N2O5)*2
rate of formation of O2
= 6.25*10^-3*2
=12.5*10^-3
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0
Answer:
0.05
Explanation:
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