Question

FOR THE REACTION PROCESS A + B ---> PRODUCTS THE RATE IS 1ST ORDER WRT A AND 2ND ORDER WRT B IF 1 MOLE OF EACH A AND B WERE INTRODUCED INTO A 1L VESSEL AND THE INITIAL RATE WAS 10^-2(mol/L)sec^-1 CALCULATE RATE WHEN HALF THE REACTANTS HAVE BEEN TURNED INTO PRODUCTS

Answer 1

Rate of reaction r = k [ A ] * [ B ]²      =  10⁻² mol/L/sec  initially

When half the reactants are consumed, the concentrations become half, assuming that solution / water remains same = 1 liter.

   rate of reaction now = k [ A ] /2  * ( [ B ] /2 )²  = 10⁻² / 8  mol/L/sec
                             = 1.25 * 10⁻³ mol /L /sec