if the diameter of a carbon atom is 0.15nm, calculate the weight of carbon when atoms are placed side by side across the length of 10^4 km
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Diameter of a Carbon atom = 0.15 * 10⁻⁹ meter
We assume that the carbon we are talking about is C 12 isotope.
Total number of atoms that fit along 10,000 km length:
n = 10,000 *10³ / 0.15 * 10⁻⁹ = 6.667 * 10¹⁶
There are Avogadro number of atoms (molecules) in a mole of any substance. One mole of carbon 12 has a molar mass M of 12 grams. Avogadro number N is 6.023 * 10²³. The mass of the carbon atoms is 1
Mass = n * M / N = 13.28 * 10⁻⁷ gm = 1.328 * 10⁻⁶ gm
We assume that the carbon we are talking about is C 12 isotope.
Total number of atoms that fit along 10,000 km length:
n = 10,000 *10³ / 0.15 * 10⁻⁹ = 6.667 * 10¹⁶
There are Avogadro number of atoms (molecules) in a mole of any substance. One mole of carbon 12 has a molar mass M of 12 grams. Avogadro number N is 6.023 * 10²³. The mass of the carbon atoms is 1
Mass = n * M / N = 13.28 * 10⁻⁷ gm = 1.328 * 10⁻⁶ gm
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