Chemistry, asked by KingAli07, 8 months ago

For the reaction R → P, the concentration of a reactant changes from 0.03 M to 0.02 M in 25 minutes. Calculate the average rate of reaction using units of time both in minutes and seconds.​

Answers

Answered by MajorLazer017
34

Given :-

  • Initial concentration of the reactant = 0.03 M.
  • Final concentration of the reactant = 0.02 M.
  • Time taken, Δt = 25 min.

To Find :-

  • Average rate of the reaction using minutes and seconds as units of time.

Solution :-

Case I (time in minutes):-

Rate = \rm{-\dfrac{{\Delta}[R]}{{\Delta}t}}

Putting the values, we get,

\implies\rm{\dfrac{-(0.02-0.03)\:mol\:L^{-1}}{25\:min}}

\implies\rm{\dfrac{0.01\:mol\:L^{-1}}{25\:min}}

\implies\bold{4\times{}10^{-4}\:mol\:L^{-1}\:min^{-1}.}

\hrulefill

Case II (time in seconds):-

Time taken = 25 min = 25 × 60 s

Again, Rate = \rm{-\dfrac{{\Delta}[R]}{{\Delta}t}}

Putting the values, we get,

\implies\rm{\dfrac{-(0.02-0.03)\:mol\:L^{-1}}{25\times{}60\:s}}

\implies\rm{\dfrac{0.01\:mol\:L^{-1}}{25\times{}60\:s}}

\implies\bold{6.67\times{}10^{-6}\:mol\:L^{-1}\:s^{-1}.}


Anonymous: Awesome
Answered by Prakshi1415
3

Answer:

Hope this helps.

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