Question

Magnetic moment of Mn^x+ is root 15 BM. The value of x is?

Answer 1

Answer:

[n(n+2)]^1/2 = [15]^1/2

Squaring both sides

n(n+2)=15n(n+2)=15

n2+2n−15=0n2+2n−15=0

Solving we get n=3n=3

Thus there are 3 unpaired electrons in the element.

The configuration of an element with atomic number 25 is [Ar]4s23d5

This configuration has electrons in the valence shell.

We have been given that the symbol of the element is Mx∗ So the value of X becomes 5−3=2

Explanation:

plzz mark as {BRAINLIST}