Question

For the reactions
A ⇋ B K꜀ = 2
B ⇋ C K꜀ = 4
C ⇋ D K꜀ = 6
K꜀ for the reaction A ⇋ D is
(a) 2 × 4 × 6 (b) 2 × 4/6
(c) 2 + 4 + 6 (d) 4 × 6/2

Answer 1

The answer is option (c)2×4×6

For the reactions

A ⇋ B

for this reaction equilibrium constant is K꜀ = 2

K꜀ = [A]/[B]

if [A] is 'x' and [B] is 'y'

then it would be x=2y .....(1)

B ⇋ C

for this reaction equilibrium constant is

K꜀ = 4

K꜀ = [B]/[C]

if [B] is y and [C] is z

then it would be 4z= y .....(2)

C ⇋ D

for this reaction equilibrium constant is

K꜀ = 6

K꜀ = [C]/[D ]

if the [D] is m

then it would be 6m= z .....(3)

for the reaction A ⇋ D

the K꜀ would be

K꜀ = [A]/[D]= x/m

and from the equation (1),(2),(3)

we can get x/m would be 48=2×4×6