Chemistry, asked by Patel2967, 8 months ago

For the reversible, one-step reaction, b + c 2 a, the forward rate constant for the formation of b is 377 m-1min-1 and the rate constant for the reverse reaction is 591 m-1min-1. the activation energy for the forward reaction is 27.4 kj/mol and that of the reverse reaction is 69.3 kj/mol. a. what is the equilibrium constant for the reaction? b. is the forward reaction exothermic or endothermic? indicate the value of the enthalpy. c. what will be the effect of raising the temperature on the rate constants and the equilibrium constant?

Answers

Answered by nirmalanagaraju01
0

Explanation:

Question 11 of 16 Mapoob Chemical Principles 7th Edition MHE/Freeman presented by Sapling Leaming For the reversible, one-step reaction shown below, k1 근 k-1 A+A B+C the rate constant for the forward reaction, k, is 291 L mol-1 min- 1and the rate constant for the reverse reaction, k1, is 383 L mor' min at a given temperature. The activation energy for the forward reaction is 43.5 kJ mol1 while the activation energy for the reverse reaction is 23.2 kJ mo1 Determine the equilibrium constant, K, of this reaction. Number K= Determine whether this reaction is endothermic or exothermic. O endothermic O exothermic

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