Question

for the same kinetic energy of a body what should be the change in its velocity if its mass is increased sixteen times

Answer 1

KE= 1/2 × m × v^2
KE' = 1/2 × 16m × x^2. ( let the changed velocity be x units/time)
KE' = KE
=> 1/2 × m × v^2 = 1/2 × 16m × x^2
=> x^2=(m/16m)× v^2
=> x^2= (v^2/16)
=> x= √[(v/16)]
=> x= v/4

Therefore Velocity should be decreased by 4 times