For the same kinetic energy of a body what should be the change in its velocity if its mass becomes 4 times
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Velocity must be halved.(i.e., v becomes v/2)
Kinetic energy(K.E.) =(mv^2)/2.
Let old mass=m. Therefore new mass is 4m.
Therefore,
K.E.=(4mv^2)/2--(1)
Now if the v is changed to v/2 then the equation(1) will become K.E.=(mv^2)/2
i.e., Kinetic energy remains the same if the velocity is halved.
Hope it helps
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