Physics, asked by shubhamgodse123456, 10 hours ago

For the same supply voltage, the power
consumed in three phase delta connected
load is ----- times the power consumed in
star connected load​

Answers

Answered by Asiaalii123
1
In a delta connected ( Dd ) group of transformers, the line voltage, VL is equal to the supply voltage, VL = VS. But the current in each phase winding is given as: 1/√3 × IL of the line current, where IL is the line current.
Answered by mithun890
0

Answer:

⇒the power consumed in three phase delta connected load is 3 times the power consumed in star conected load.

⇒ I will attach the figuers of each delta connection and star connection below check it out!

Explanation:

  • The resistance of both the delta and star is same.
  • Now let,   V_{L,D} = V_{L,Y} = V_{L}

where ,

V_{L,D} =  voltage of load in delta connection.

V_{L,Y}  = voltage of load in star connection.

(i) In Δ- connection:

  • V_{L} = V_{P,D}
  • PΔ =3 × V_{P,D} × I_{P,D}
  • PΔ = 3 × 10 × 10         { check the figure below you can get idea of, }

                                          {    these values V_{P,D} =10  & I_{P,D} = 10   }          

           ∴ PΔ = 3oow ⇒  eq no:1

(ii) In star connect

  • V_{L} = V_{L,Y}
  • PΥ= 3 × V_{P,Y} I_{P,Y}

 { check the figure below you can get  idea of  these values}

  • PΥ= {3} × 10/\sqrt{3} × 10/\sqrt{3}
  • PΥ= 100w ⇒ eq no:2

from both eq no 1&2 we can say that,

    PΔ= 3PΥ.

∴ power consumed in three phase delta connected load is 3 times the power consumed in star conected load.

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