Question

For the sequence tn= n² -2n, find the third term​

Answer 1

Here,

tn = n²-2n

when,

n= 1

t1 = (1)²-2n = 1 -2×1 = -1

when,

n=2

t2 = (2)²-2×2 = 4-4= 0

when,

n=3

t3 = (3)²- 2×3 = 9-6=3

So, the 3rd of the sequence is 3.