Question

. For the series combination of three resistors establish the relation R= R1 +R2 +R3 . Also
calculate the equivalent resistance of the combination of three resistors of 6 Ω , 9 Ω, 18 Ω
joined in parallel.

Answer 1

Answer:3 ohms

Explanation:

By Formula for Resistors connected in Parallel,

1/R1 + 1/R2 + 1/R3 =1/R

Where R is equivalent Resistance.

1/6 + 1/9 +1/18 =1/R

1/R = 3/18 + 2/18 + 1/18

1/R = 6/18

1/R =1/3

So, R=3 ohms