. For the series combination of three resistors establish the relation R= R1 +R2 +R3 . Also
calculate the equivalent resistance of the combination of three resistors of 6 Ω , 9 Ω, 18 Ω
joined in parallel.
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Answer:3 ohms
Explanation:
By Formula for Resistors connected in Parallel,
1/R1 + 1/R2 + 1/R3 =1/R
Where R is equivalent Resistance.
1/6 + 1/9 +1/18 =1/R
1/R = 3/18 + 2/18 + 1/18
1/R = 6/18
1/R =1/3
So, R=3 ohms
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