Question

For the sets X = {10, 11, 12, 13, ..., 17, 18},
A = {11, 13, 15), B = (12, 14, 16), show that B^C - A^C = A - B = A⋂B^C​

Answer 1

Answer:

10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 1. In a city ... Then P(A ∪ B) = (a) 11 40 31 40 (b) (c) 21 40 1 40 (d) 7.

Answer 2

Step-by-step explanation:

A^c = compliment of set A, also denoted with '.

A' = {10,12,14,16,17,18}

B' = {10,11,13,15,17,18}

B' - A' = {11,13,15} (common nos. between B' and A' from the set B'}

A - B = {11,13,15} (common nos. between A and B from the set A)

A ∩ B' = {11,13,15} (common nos. between A and B')

thus, B' - A' = A - B = A ∩ B' [PROVED}