Question

for the simple harmonic oscillator at the mean position​

Answer 1

Answer:

Explanation:

kinetic energy is minimum, potential energy is maximum. E=12k(A2-x2),U=1/2kx^(2)Atthemeanpositionx=0∴K.E.=1/2kA^(2)=Maximum andU=0. .

Answer 2

Answer:

(a) kinetic energy is minimum, potential energy is maximum. E=12k(A2-x2),U=1/2kx^(2)Atthemeanpositionx=0∴K.E.=1/2kA^(2)=Maximum andU=0. ...