For the sumof the first n terms of an A. P. Sn
=
O n/2[11+ tn)
O n/2'[a + (n - 1)d)
0 n/3[2 + (m - 1)d]
Oa/2 [1 + (n − 1)d]
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tfjkgvgujnvg98uiutgjugxft6hvd56gff
Answered by
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Answer:
Sn= n/ 2 [ 2a + (n- 1) d]
I hope it will help you
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