. For the triangle ABC, the base BC = 20 cm. AB = 15 cm, AC = 7 cm. Compute the height of the triangle AD.
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Given :-
- AB = 15cm.
- BC = 20cm.
- AC = 7cm.
To Find :-
- AD = ? (Height)
Solution :-
→ Semi - Perimeter of ∆ABC = (Perimeter)/2 = (20 + 15 + 7)/2 = 21 cm.
So,
→ Area of ∆ABC = √{s(s - a)(s - b)(s - c)} [ Heron's formula. ]
( a, b and c are sides of ∆. )
Putting all values we get,
→ Area = √{21 * (21 - 20)(21 - 15)(21 - 7)}
→ Area = √(21 * 6 * 14)
→ Area = √(3 * 7 * 3 * 2 * 2 * 7)
→ Area = √(2² * 3² * 7²)
→ Area = (2 * 3 * 7)
→ Area = 42 cm².
Now, we also know that,
→ Area of ∆ = (1/2) * Base * Height
Given base is 20cm.
Therefore,
→ (1/2) * 20 * Height = 42
→ 10 * Height = 42
dividing both sides by 10,
→ Height = 4.2 cm.
Hence, AD is Equal to 4.2 cm.
Learn More :-
1. In ∆ ABC, AD is a median. If AB = 8, AC = 15
and AD = 8.5, find BC.
https://brainly.in/question/22467548
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