Question

For the two independent events A and B P(AU B) = 0.9 and P(A) = 0.6, then find P(B).​

Answer 1

Answer:

p ( AUB) = P (A) + P (B) - P ( A intersection B)

p (A U B) = p (A) + p (B) - p (A) . p ( B)

0.9= 0.6 + p (B) - 0.6 .p(B)

0.9- 0.6= p(B) - 0.6 p (B)

0.3 = p (B) [1-0.6]

0.3= P (B) . 0.4

P (B) = 0.3 / 0.4

p (B) = 0.75