for the value of k are the number x,2x+K and 3x+6 three consecutive terms of an ap
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Answered by
5
In an ap
a1 = x
a2 = 2x+k
a3 = 3x+6
then,
a2 - a1 =a3 - a2
2x+k - x =3x+6-2x-k
x+k=x-k+6
2k =6
k = 3
I hope this help u
a1 = x
a2 = 2x+k
a3 = 3x+6
then,
a2 - a1 =a3 - a2
2x+k - x =3x+6-2x-k
x+k=x-k+6
2k =6
k = 3
I hope this help u
Answered by
3
in an ap,
2x+k-x=3x+6-(2x+k)
x+k=3x-6-2x-k
2k=3x-2x-x-6
2k=-6
k=-3
2x+k-x=3x+6-(2x+k)
x+k=3x-6-2x-k
2k=3x-2x-x-6
2k=-6
k=-3
Sanaya625:
You have q mistake check your answer
no
Are in third line this is not -6 this is +6
ohh yes u r rit
Hmmm
yes its +6 instead of -6 in third line....srry for this mistake
Its okk yrr
hmkkk
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