Question

For the value of K, the root of quadratic equation x ^ -2 (1 + 3k) x + 7 (3 + 2k) = 0 is 7.
please very urgent

Answer 1

Put the value of x =7 and then solve

7^2+(1+3k)7+7(3+2k)=0

49+7+21k+21+14k=0

77+35k=0

7(11+5k)=0

11+5k=0

K= -11/5

.........:)