Question

for the what value of p the quadratic equation x2-4X+p=0 will have real and equal roots?​

Answer 1

Answer:

p= 4

Step-by-step explanation:

D= b²-4ac

for real and equal roots, D must be equal to zero

               ∴a=1

                b=-4

                 c=p

sub in quadratic eqn

D = (-4)²-4×1×p=0

16-4p=0

-4p= 0-16

-4p=-16

4p=16

p=4

if my answer is correct please mark me the brainliest