Question

for the write five situations following where would braketes be nessacary. bes a 7 (8-3) 47+2) (10-3​

Answer 1

Answer:

(7+2)(10−3)

[we will open one of the brackets]

7(10−3)+2(10−3)

={(7×10)−(7×3)+{(2×10−2×3)}

={70−21}+{20−6}

=49+14

=63.

Answer 2

Answer:

sorry I didn't know the answer