Question

For traffic moving at 60 km per hour if the radius of the circular curve of a highway is 0.1 kilometre what is the correct angle of banking of the road take G is equals to 10 M per second square given tan inverse 0.27 8 is equals to 15.5 degree

Answer 1

Answer:

15.5°

Explanation:

According to the given data of the question,

We have

velocity = v = 60 km/hr =16.67 m/s

As we know that 1 km = 1000 m and 1 hour = 3600 sec.

Radius = r = 0.1 km = 100 m

G = 10 m/s

Formula used for the angle of banking of the road is given by:

$tan\theta=\frac{v^{2}}{r \times G}$

Now on putting the given values, we get

$tan\theta = \frac{16.67^{2}}{100 \times 10}$

$tan\theta = 0.278$

$\theta =tan^{-1} \ (0.278)$

$\theta = 15.5$

∴ θ = 15.5°

Hence, the correct angle of banking of the road = 15.5°

Answer 2

15.5 degrees

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