Question

for
transistor
Alfa=0.96
find the value of ß​

Answer 1

Explanation:

$\alpha = \frac{ \beta }{1 + \beta } \\ 0.96 = \frac{ \beta }{1 + \beta } \\ \frac{96}{100 } = \frac{ \beta }{1 + \beta } \\ 96 + 96 \beta = 100 \beta \\ 96 = 100 \beta - 96 \beta \\ 96 = 4 \beta \\ \beta = \frac{96}{4} \\ \beta = 24$

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