for traveling in an auto fixed charge will be taken and for no of kms travelled extra charge per km will be take. he paid Rs 1000 for travelling 20 km distance and Rs 1180 for 26 km find fixed charge and amount for 1 km
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i. Let the fixed charge be x.
Let the charges per km be y.
Total charges to be paid will be the sum of the fixed charges and the charges per km.
For 10kms, the amount paid is ₹220.
x + 10y = 220 …I
For 15kms, the amount paid is ₹ 310
x + 15y = 310 …II
Solving I and II we get
x + 10y = 220
x + 15y = 310
- - -
-5y = -90
y = 18
Substituting the value of y in Eq. I we get
x + 10(18) = 220
x = 220 – 180
x = 40
The Fixed charge are ₹ 40 and the charges per km are ₹18
ii. For 25 km ,
total = 40 + 25(18) = 40 + 450 = 490
hence, for 25 km, the taxi fare is 490
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ꆰꀎꏂꌚ꓄ꀤꂦꈤ
=>for traveling in an auto fixed charge will be taken and for no of kms travelled extra charge per km will be take. he paid Rs 1000 for travelling 20 km distance and Rs 1180 for 26 km find fixed charge and amount for 1 km
=>for traveling in an auto fixed charge will be taken and for no of kms travelled extra charge per km will be take. he paid Rs 1000 for travelling 20 km distance and Rs 1180 for 26 km find fixed charge and amount for 1 km
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