Question

for two forces p and Q acting at a point maximum resultant is 300 N and minimum magnitude is 800 N find the value of p and Q​

Answer 1

GIVEN :-

• Two force P and Q .
• Maximum resultant = 300.
• Minimum resultant = 800 N.

TO FIND :-

• The value of P and Q.

SOLUTION :-

The maximum resultant force can be written as,

$\implies \sf \: P + Q = 300....(1)$

The minimum resultant force can be written as,

$\implies \sf \: P - Q = 800....(2)$

From equation 1 we have,

$\implies \sf \: P = 300 - Q ....(3)$

From equation 2 we have,

$\implies \sf \: P = 800 + Q ....(4)$

On comparing equation 3 and 4 we get,

$\implies \sf \: 300 - Q = 800 + Q$

$\implies \sf \: - 2Q = 500$

$\implies \sf \: - Q = \dfrac{500}{2}$

$\implies \sf \: Q = - 250$

Now substitute the value of Q in equation 1,

$\implies \sf \: P - 250 = 300$

$\implies \sf \: P= 300 + 250$

$\implies \sf \: P=550$

Hence the value of P is 550 and value of Q is -250.

Answer 2

Question:-

• For two forces p and Q acting at a point maximum resultant is 300 N and minimum magnitude is 800 N find the value of p and Q.

Given that:-

• Two forces p and Q acting at a point maximum resultant is 300 N.
• Minimum magnitude is 800 N

To Find:-

• Find the value of P and Q.

Solution:-

• P + Q = 300 N . . . . ( 1 )
• P = 300 - Q . . . . ( 2 )
• P - Q = 800 N . . . . ( 3 )
• P = 800 + Q . . . . ( 4 )

First ,

Compare equation ( 2 ) and ( 3 ):-

➝ 300 - Q = 800 + Q

➝ 2Q = - 500

➝ Q = - 500/2

➝ Q = - 250

Now ,

We have to find the value is P so, substitute in equation ( 1 ):-

➝ P - 250 = 300

➝ P = 300 + 250

➝ P = 550

Hence ,

• The value of P is 550 and Q is - 250