Question

For vaporization of water at 1 atmospheric
pressure, the values of AH and AS are 40.63 kJ
mol-1 and 108.8 JK-1 mol-1 respectively. The
temperature when Gibbs energy change (AG) for
this transformation will be zero, is​

Answer 1

Explanation:

we know G=H-T∆S for G=0

H=T∆S

so putting the values t=40.63×1000÷108.8

comes to be 3682K temp

ans is correct as per the data given

Answer 2

HOPE YOU GIVE ME BRAINLIEST!!!

Answer:

T=373.4 K

Explanation:

We know,

G= H-TS

If G=0

0=H-TS

H=TS

T=H/S

T=(40.63*1000)/108.8

T=40630/108.8

T=373.4 K