Question

For what energy a proton will the associated de-broglie wavelength be 16.5 nm

Answer 1

Answer: kinetic energy

Explanation:

Here, λ=16.5nm=16.5×10−9m

K.E. of proton,

K=12(mv2)=12m(mv2)=12mh2λ2

=(6.63×10−34)22×(1.675×10−27)×(16.5×10−9)2

=4.82×10−25J