Math, asked by dscmajestic, 22 hours ago

for what least value of n 4^n is divisible by 8

Answers

Answered by sarveshjajoo
2

Answer:

n=2

Step-by-step explanation:

since 4^2 is=16 is divisible by 8

Answered by Amido23
0

4^n = 8

from trial and error method obviously

if n = 0

4^0 = 1

if n =1

4^1 = 4

if n=2

4^2 = 8

8/8 = 1

and

8%8 = 0

hence n = 2

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