for what value 'a ' is (x-5) a factor of X3 - 3X2 + ax -10
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q(x)=x-5=0
x=5
since p(x) has a factor so p(x)=0
x^3-3x^2+ax-10=0
(5)^3-3(5)^2+a(5)-10=0
125-75+5a-10=0
40+5a=0
5a=-40
a=-8
x=5
since p(x) has a factor so p(x)=0
x^3-3x^2+ax-10=0
(5)^3-3(5)^2+a(5)-10=0
125-75+5a-10=0
40+5a=0
5a=-40
a=-8
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