for what value k,x=2 and y=-1 is a solution of x+3y-k=0
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Answered by
1
x=2
y=-1
x+3y-k=0
2+3×-1=k
-1=k
y=-1
x+3y-k=0
2+3×-1=k
-1=k
Answered by
24
if x = 2 and y = -1
then ,
x+3y-k = 0
2+3×-1 -k = 0
k = -1
then ,
x+3y-k = 0
2+3×-1 -k = 0
k = -1
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