For what value of a, are (2a-1), 7 and 3a three consecutive terms of an A.P?
Answers
Answered by
4
Step-by-step explanation:
if the terms are in ap it means
2b=a+b
7=(2a-1)+3a
7+1=5a
a=8/5
so terms are
11/5,7,24/5
Answered by
14
✨Given:✨
Three terms
- First term = (2a-1)
- Second Term = 7
- Third Term = 3a
✨To Find:✨
Value of a for which the above three terms are in an AP
✨Concept:✨
For three terms to be in AP , the sum of first and third term should be equal to twice the second term.
For three terms a , b and c to be in an AP:
2b = a + c
✨Answer:✨
From using the above concept, we get:
2 * 7 = 2a - 1 + 3a
5a - 1 = 14
5a = 14 + 1
5a = 15
a =
a = 3
Therefore, the value of a is 3.
First Term = 2*3 - 1 = 6 - 1 = 5
Second Term = 7
Third Term = 3*3 = 9
✨Proof:✨
Substituting the value of a in the terms, we get:
First Term = (2*3 - 1) = 5
Second Term = 7
Third Term = 3*3 = 9
2b = a + c
2*7 = 5 + 9
14 = 14
LHS = RHS
Hence Proved.
✨Other AP Formulas:✨
⭐nth term of an AP
formulas⭐
where m and n is the position of the term in the AP
⭐Sum Formulas⭐
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