Question

for what value of 'a' is the polynomial x^3 + 2x^2 - 3ax - 8 a multiple of x-4​

Answer 1

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Answer 2

Answer:

p(x) = x³ + 2x² - 3ax - 8

x - 4 = 0

x = 4

p(4) = (4)³ + 2(4)² - 3a(4) - 8

64 + 32 - 8 - 12a = 0

96 - 8 - 12a = 0

88 - 12a = 0

a = 88/12

a = 22/3