Question

for what value of a quadratic equation 30ax²-6x+1 has no real roots
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Answer 1

Answer:

a > 3/10

Step-by-step explanation:

30ax²-6x+1 =0

If Root are not real then

b² <4ac

here a=30a,b=-6 c=1

so (-6)² < 4*(30a)*1

36 < 120a

120a  > 36

a > 36/120

a > 3/10

Answer 2

Answer:

a > 3 / 10

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