Question

For what value of a the block falls freely?​

Answer 1

Answer:

In the time the wedge moves a distance 'x' towards left with an acceleration 'a' the block falls from a height 'h' with accelerating 'g'

$x = \frac{1}{2} a {r}^{2}$

$h = \frac{1}{2} g {r}^{2}$

$= > \frac{x}{h } = \frac{a}{g}$

$cot \: θ = \frac{a}{g}$

$a = g \: cot \: θ$

Explanation:

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