Question

for what value of c the linear equation 2×+cy =8 has equal values of × and y for its solution​

Answer 1

Answer:

Step-by-step explanation:

Assume that positive integer solutions are wanted for 2x+cy=8.

x and y have equal values

⟹x=y.

The equation becomes 2x+cx=8

⟹x(2+c)=8

⟹x=82+c.

x is a positive integer when c=0, 2, or 6

c=0⟹2x+0y=8

⟹2x=8

⟹x=4 and y=any number;

c=2⟹2x+2y=8  

⟹x=y=2, so this value of c works;

c=6⟹2x+6y=8

⟹x=y=1, so this value of c works too.

∴c=2, 6 is the answer.

hope it helps

Answer 2

Hi ,

pls mark on brain list pls

According to the problem given,

2x + cy = 8 ------ ( 1 )

And

x = y -------------( 2 )

Put y = x in equation ( 1 ) we get ,

2x + cx = 8

Take x common

x ( 2 + c ) = 8

x = 8 / ( 2 + c )

But denominator should not be zero

2 + c not equals to zero

c is not equals to -2

and c = 0 , 2 and 6 satisfies the condition

2x + cy = 8

has equal values of x and y.

I hope this helps you.

:)