Question

For what value of k , 3 2 x x kx −++ 543 is divisible by ( 3) x − a) 5 4 b) 1 c) 3 2 d) 4 5​

Answer 1

Answer:

Let f(x)=2x

3

+3x

2

−kx+5

By remainder theorem, when f(x) is divided by (x−2)

x−2=0,⇒x=2

the remainder =f(2)

=2(2)

3

+3(2)

2

−k(2)+5

=16+12−2k+5

=33−2k

According to question

33−2k=7

⇒2k=26

⇒k=13