Question

For what value of k , (-4) is a zero of the polynomial x^2-x-(2k+2)?

Answer 1

Answer:

f(-4)=x^2-x(2k+2)

0=(-4)^2-(-4)-(2k+2)

0=16+4-2k-2

2k=18

k=9

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Answer 2

Answer:

9

Step-by-step explanation:

f(x)= x^2-x-(2k+2)

f(-4)= (-4)^2 - (-4) -(2k+2)

now, 16+4-2k-2 = 0

18 - 2k = 0

So, k = 18÷2

= 9