Question

For what value of k,(-4) is a zero of the polynomial x²-x-(2k+2)?

Answer 1

Answer:

Step-by-step explanation:

-4 is zero value for p(x)=

p(-4)=0

substitute -4 in in polynomial

(-4)^2-(-4)-(2k+2)=0

16+4–2k-2=0

20–2k-2=0

18–2k=0

-2k=-18

k=9

Answer 2

Answer:

Zero of the polynomial is -4

p(x)=x²-x-(2k+2)

p(x)=x²-x-2k-2

p(-4)=0

0=-4²-(-4)-2k-2

0=16+4-2k-2

0=18-2k

2k=18

k=18/2=9

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