Question

for what value of k (-4) is zero of polynomial x ^2-x-( 2 k + 2)​

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Answer 1

Polynomial = x²-x-(2k+2)

= x²-2kx+2

PUTTING 4 IN THE POLYNOMIAL

x²-2kx+2

= 4² - (2k * 4) + 2

= 16 - 8k + 2 = 0

= 18 - 8k = 0

-8k = -18

k = -18/-8

k = 18/8

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Answer 2

Answer:

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Step-by-step explanation:

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