Question

For what value of k are 2k,k+10 & 3k+2 in A.P.

Answer 1

2k,k+10,3k+2
$a = 2k \\ b = k + 10$
common difference =
(second term- first term)=d= (third term-second term)
(k+10-2k)=(3k+2-k-10)
-k+10=2k-8
10+8=2k+k
18=3k
k=18/3=6
value of k is 6

Answer 2

Hi friend,

Here is your answer,

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If 2k , k+10 and 3k+2 then the common difference would be same ...
  3k+2-k-10 = k+10-2k
  2k-8 = 10-k
      3k = 18
        k = 6
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