Math, asked by prachirathod2007, 4 months ago

For what value of k are k+9, 2k-1, 2k+7 are in A.P

Answers

Answered by pubggrandmaster43
7

Answer:

k = 18

Step-by-step explanation:

k+9, 2k-1, 2k+7 are in A.P

so, the difference between A.P is equal

(2k - 1) - (k + 9) = (2k + 7) - (2k - 1)

2k - 1 - k - 9 = 2k + 7 - 2k + 1

k - 10 = 8

k = 8 + 10

k = 18

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