Math, asked by Gudveshsinghania, 1 year ago

For what value of k are the root quadratic equation bx(x- 2) +6 = 0 equal?


yadav9sakshi: where is k
Gudveshsinghania: constant term
Gudveshsinghania: sorry sir b ka place par k hoga
Gudveshsinghania: hlo sir

Answers

Answered by kalyaniprasad8
0

Given equation,

kx(x-2)+6=0

kx^2-2kx+6=0

As roots are equal,

Discriminant=0

b^2-4ac=0

(-2k)^2-4*k*6=0

4k^2=24k

k=6

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