Question

for what value of k are the root quadratic equation kx( x-2) +6 =0 equal?

Answer 1

kx²-2kx+6=0

4k2-24k=0

k²=6k
k=6

Answer 2

Given equation,

kx(x-2)+6=0

kx^2-2kx+6=0

As roots are equal,

Discriminant=0

b^2-4ac=0

(-2k)^2-4*k*6=0

4k^2=24k

k=6