For what value of k are the roots of the quadratic equation kx2 + 4x + 1 = 0 equal and real?
Answers
Answered by
92
★ QUADRATIC RESOLUTION ★
For real and equal roots ; D = 0
GIVEN EQUATION → kx² + 4x + 1 = 0
D = 0
16 - 4 ( k ) = 0
HENCE , k = 4
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For real and equal roots ; D = 0
GIVEN EQUATION → kx² + 4x + 1 = 0
D = 0
16 - 4 ( k ) = 0
HENCE , k = 4
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Answered by
111
Helloo!!
a=k b=4 & c=1
d=0
16-4ac=0
16-4k=0
16=4k
k=16/4
k=4
therefore k = 4
Hop it helps!!
a=k b=4 & c=1
d=0
16-4ac=0
16-4k=0
16=4k
k=16/4
k=4
therefore k = 4
Hop it helps!!
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